A spherical iron ball 10 cm in radius is coated with a layer of ice of uniform thickness…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
A spherical iron ball 10 cm in radius is coated with a layer of ice of uniform thickness that melts at a rate of 50 cm3/min. When the thickness of ice is 5 cm, then the rate at which the thickness of ice decreases, is
- \(\frac{1}{18 \pi} \mathrm{~cm} / \mathrm{min}\)
- \(\frac{1}{36 \pi} \mathrm{~cm} / \mathrm{min}\)
- \(\frac{5}{6 \pi} \mathrm{~cm} / \mathrm{min}\)
- \(\frac{1}{54 \pi} \mathrm{~cm} / \mathrm{min}\)
Answer
(A) 1 18 ~cm / min
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