_ x 4 _ 2 ^ ^ 2 x f(t) d t x^ 2 - ^ 2 16 equals
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
\[\lim _{x \rightarrow \frac{\pi}{4}} \frac{\int_{2}^{\sec ^{2} x} f(t) d t}{x^{2}-\frac{\pi^{2}}{16}}\] equals
- \(\frac{8}{\pi} f(2)\)
- \(\frac{2}{\pi} f(2)\)
- \(\frac{2}{\pi} f\left(\frac{1}{2}\right)\)
- \(4 \mathrm{f}(2)\)
Answer
(A) 8 f(2)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let g´ (x) > 0 and f ’ (x) < 0, x ∈ R, then
- The least area of a circle circumscribing any right triangle of area S is :
- _ x 0 ( 1+5 x^ 2 1+3 x^ 2 )^ 1 / x^ 2 is equal to
- Find the value of a for which the function f (x) = x 2 - 2ax + 6 is strictly increasing when x > 0.
- A function is defined as follows : f(x)= array cc x^ 3 ; & x^ 2 <1 x ; & x^ 2 1 array . The function is
- If y= x+e^ x then d^ 2 x d y^ 2 is equal to
- _ x 0 1 x x(21) is equal to
- Consider a function f( x )= ( - 1 - x ) (4 – 3x 2 ) where ‘α’ is a positive parameter Absolute difference…
More Limit, Continuity and Differentiability questions · Browse all practice questions