Find the set of values of ‘x’ for which the given condition is true (x – 1) (x – 3) (x +…

Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions

1. (–5, 1) ∪ (3, ∞)
2. (–1, 5)
3. [–5, 1] ∪ [3, ∞)
4. none of these

Answer

(A) (–5, 1) ∪ (3, ∞ )

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• Let A = R - 3 , B = R - 1 , Let f : A → B be defined by f(x) = x-2 x-3 , then
• If a function f(x) satisfies the condition f (x+ 1 x )=x^ 2 + 1 x^ 2 ,(x 0) , then f(x) equals
• Considering only the principal values of the inverse trigonometric functions, the domain of the function…
• If f(x)= 2 x-1 x+5 (x -5) then f^ -1 (x) is equal to :
• If ^ -1 ( a x )+ ^ -1 ( ~b x )= 2 , then x is equal to :
• The value of _ r=0 ^ ^ -1 ( 1 1+r+r^ 2 ) is equal to :
• If x 2 + 6x – 27 > 0 and x 2 – 3x – 4 < 0, then
• Let W denotes the words in the English dictionary. Define the relation R by R = (x, y) ∈ W × W : the words x…

More Sets, Relations and Functions questions · Browse all practice questions