If x 2 + 6x – 27 > 0 and x 2 – 3x – 4 < 0, then
Mathematics · JEE Main · NTA Exams — Sets, Relations and Functions
If x2 + 6x – 27 > 0 and x2 – 3x – 4 < 0, then
- x > 3
- x < 3
- 3 < x < 4
- x = 7/2
Answer
(C) 3 < x < 4
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