If x 2 + 6x – 27 > 0 and x 2 – 3x – 4 < 0, then

Mathematics · JEE Main · NTA ExamsSets, Relations and Functions

If x2 + 6x – 27 > 0 and x2 – 3x – 4 < 0, then
  1. x > 3
  2. x < 3
  3. 3 < x < 4
  4. x = 7/2

Answer

(C) 3 < x < 4

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