For the following cell, (2017) Zn ( ~s ) | ZnSO _ 4 ( aq ) CuSO _ 4 ( aq ) | Cu ( ~s )…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
For the following cell, (2017)
\(\mathrm{Zn}(\mathrm{~s})\left|\mathrm{ZnSO}_{4}(\mathrm{aq}) \| \mathrm{CuSO}_{4}(\mathrm{aq})\right| \mathrm{Cu}(\mathrm{~s})\)
When the concentration of \(\mathrm{Zn}^{2+}\) is 10 times the concentration of \(\mathrm{Cu}^{2+},\) the expression for \(\Delta \mathrm{G}\) (in J mol–1) is
[F is Faraday constant; R is gas contant; T is temperature; Eº (cell) = 1.1 V]
\(\mathrm{Zn}(\mathrm{~s})\left|\mathrm{ZnSO}_{4}(\mathrm{aq}) \| \mathrm{CuSO}_{4}(\mathrm{aq})\right| \mathrm{Cu}(\mathrm{~s})\)
When the concentration of \(\mathrm{Zn}^{2+}\) is 10 times the concentration of \(\mathrm{Cu}^{2+},\) the expression for \(\Delta \mathrm{G}\) (in J mol–1) is
[F is Faraday constant; R is gas contant; T is temperature; Eº (cell) = 1.1 V]
- 2.303 RT + 1.1F
- 1.1 F
- 2.303 RT – 2.2F
- – 2.2 F
Answer
(C) 2.303 RT – 2.2F
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