1.08 g of pure silver was converted into silver nitrate and its solution was taken in a…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
1.08 g of pure silver was converted into silver nitrate and its solution was taken in a beaker. It was electrolysed using platinum cathode and silver anode. 0.01 Faraday of electricity was passed using 0.15 volt above the oxidation potential of silver. The silver content of the beaker after the above shall be
- 0 g
- 0.108g
- 0.108 g
- 1.08 g
Answer
(A) 0 g
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- For the following electrochemical cell at 298 K, Pt ( s ) |H 2( g ) , (1 bar)|H + ( aq ) , (1 M)|| M 4 + ( aq…
- When 9.65 coulombs of electricity is passed through a solution of silver nitrate (atomic mass of Ag = 108 g…
- If 0.01 M solution of an electrolyte has a resistance of 40 ohms in a cell having a cell constant of 0.4 cm…
- Molar ionic conductivities of a two-bivalent electrolytes x 2+ and y 2– are 57 and 73 respectively. The molar…
- At an anode in an electrolytic cell where electrolysis is taking place, which of the following processes must…
- The concentration of potassium ions inside a biological cell is at least twenty times higher than the…
- Specific conductance of 0.1 M sodium chloride solution is 1.06 × 10 –2 ohm –1 cm –1 . Its molar conductance…
- Standard potentials (Eº) for some half-reactions are given below : (I) Sn 4+ + 2 e ^ - → Sn 2+ ; Eº = + 0.15…
More Electrochemistry questions · Browse all practice questions