In the binomial expansion of (a – b) n , n ≥ 5, the sum of the 5 th and 6 th terms is…
Mathematics · JEE Advanced · NTA Exams — Binomial Theorem And Its Simple Applications
In the binomial expansion of (a – b)n, n ≥ 5, the sum of the 5th and 6th terms is zero. Then, a/b equals
- \(\frac{n-5}{6}\)
- \(\frac{n-4}{5}\)
- \(\frac{5}{n-4}\)
- \(\frac{6}{n-5}\)
Answer
(B) n-4 5
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