If s_ n = _ r=0 ^ n 1 ^ n C_ r and t_ n = _ r=0 ^ n r ^ n C_ r then t_ n s_ n is equal to
Mathematics · JEE Advanced · NTA Exams — Binomial Theorem And Its Simple Applications
If \(s_{n}=\sum_{r=0}^{n} \frac{1}{{ }^{n} C_{r}} \text { and } t_{n}=\sum_{r=0}^{n} \frac{r}{{ }^{n} C_{r}} \text { then } \frac{t_{n}}{s_{n}}\) is equal to
- \(\frac{\mathrm{n}}{2}\)
- \(\frac{\mathrm{n}}{2}-1\)
- n – 1
- \(\frac{2 n-1}{2}\)
Answer
(A) n 2
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