30 0 30 10 - 30 1 30 11 + .+ 30 20 30 30 =
Mathematics · JEE Advanced · NTA Exams — Binomial Theorem And Its Simple Applications
\(\binom{30}{0}\binom{30}{10}-\binom{30}{1}\binom{30}{11}+\ldots .+\binom{30}{20}\binom{30}{30}=\)
- 65C55
- 30C10
- 60C10
- 30C11
Answer
(C) 60 C 10
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