The coefficient of x 7 in the expansion of (1 – x – x 2 + x 3 ) 6 is
Mathematics · JEE Advanced · NTA Exams — Binomial Theorem And Its Simple Applications
The coefficient of x7 in the expansion of (1 – x – x2 + x3)6 is
- –144
- 132
- 144
- –132
Answer
(D) –132
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The sum 1 . 20 C 1 –2 . 20 C 2 + 3 . 20 C 3 – .....– 20 C 20 is equal to
- Match the entries in Column-I representing in n with their values given in Column-II.
- The term independent of x in the expansion of (1 + x) n (1+ 1 x )^ n is :
- The coefficient of x 4 in ( x 2 - 3 x^ 2 )^ 10 is
- If A = 2n C 0 . 2n C 1 + 2n C 1 2n–1 C 1 + 2n C 2 2n–2 C 1 + .....then A is
- If C r stands for n C r , then the sum of the series 2 ( n 2 )! ( n 2 )! n ! [ C _ 0 ^ 2 -2 C _ 1 ^ 2 +3 C _…
- 1 . n C 1 + 2, n C 2 + 3 . n C 3 + ....+ n. n C n is equal to
- If 1 1-2 x+x^ 2 =1 + a 1 x + a 2 x 2 + ..., then the value of a r is
More Binomial Theorem And Its Simple Applications questions · Browse all practice questions