1 . n C 1 + 2, n C 2 + 3 . n C 3 + ....+ n. n C n is equal to
Mathematics · JEE Advanced · NTA Exams — Binomial Theorem And Its Simple Applications
1 . nC1 + 2, nC2 + 3 . nC3 + ....+ n. nCn is equal to
- \(\frac{\mathrm{n}(\mathrm{n}+1)}{4} \cdot 2^{\mathrm{n}}\)
- 2n+1–3
- n2n–1
- none of these
Answer
(C) n2 n–1
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