If 1 - 25 x^2 dx = 5x 2a 1 - 25x^2 + 1 2a ^ -1 5x + C , then value of a is:
Mathematics · Class 12 · CBSE — Integrals
If \(\int \sqrt{1 - 25 x^2}\,dx = \dfrac{5x}{2a}\sqrt{1 - 25x^2} + \dfrac{1}{2a}\sin^{-1} 5x + C\), then value of \(a\) is:
- \(25\)
- \(5\)
- \(2\)
- \(1\)
Answer
(B) 5
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- _0^ 2a f(x) dx = 2 _0^a f(x) dx iff f(2a - x) is equal to:
- Assertion (A): dx x^2 + 2x + 3 = 1 2 ^ -1 ( x+1 2 ) + C . Reason (R): dx x^2 + a^2 = 1 a^2 ^ -1 x a + C .
- Evaluate :
- If d dx f(x) = 2x^3 - 1 x^2 such that f(1) = 1 , then f(x) is equal to:
- Assertion (A): _ -1 ^ 1 (x^3 + x + 2) dx = 0 . Reason (R): _ -a ^ a f(x) dx = cases 2 _0^a f(x) dx, & if f(x)…