If d dx f(x) = 2x^3 - 1 x^2 such that f(1) = 1 , then f(x) is equal to:
Mathematics · Class 12 · CBSE — Integrals
If \(\dfrac{d}{dx} f(x) = 2x^3 - \dfrac{1}{x^2}\) such that \(f(1) = 1\), then \(f(x)\) is equal to:
- \(\dfrac{x^4}{2} + \dfrac{1}{x}\)
- \(\dfrac{x^4}{2} - \dfrac{1}{x} - \dfrac{1}{6}\)
- \(\dfrac{x^4}{2} + \dfrac{1}{x} - \dfrac{1}{2}\)
- \(\dfrac{x^4}{2} + \dfrac{1}{x} + \dfrac{1}{2}\)
Answer
(A) x^4 2 + 1 x
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