Let z 1 and z 2 be two roots of the equation z 2 + az + b = 0, z being complex. Further…
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
Let z1 and z2 be two roots of the equation z2 + az + b = 0, z being complex. Further, assume that the origin, z1 and z2 form an equilateral triangle, then
- a2 = 2b
- a2 = 3b
- c2 = ab
- a2 = b
Answer
(B) a 2 = 3b
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let a, b, c ∈ R. If ax 2 + bx + c = 0 has two real roots A and B where A 1, then
- If z 0 , z 1 represents points P, Q on the locus |z–1|=1 and the line segment PQ subtends an angle 2 at the…
- If α, β are the roots of the quadratic equation, x 2 – 2p (x – 4) – 15 = 0 then the set of values of p for…
- If a complex number z has modulus 1 and argument π/3, then z 2 + z
- If the expression x 2 – 11x + a and x 2 – 14x + 2a must have a common factor and a ≠ 0, then, the common…
- Let S= a+b 2 : a, b Z , T_ 1 = (-1+ 2 )^ n : n N , and T_ 2 = (1+ 2 )^ n : n N . Then which of the following…
- If z 2 – z + 1 = 0, then z n – z –n , where n is a multiple of 3, is
- If θ ∈ (0, π), the principal value of the arg (z) and |z| of the complex number z= (1+ +i )^ 5 ( +i )^ 3 is
More Complex Numbers and Quadratic Equations questions · Browse all practice questions