Let a, b, c ∈ R. If ax 2 + bx + c = 0 has two real roots A and B where A 1, then
Mathematics · JEE Advanced · NTA Exams — Complex Numbers and Quadratic Equations
Let a, b, c ∈ R. If ax2 + bx + c = 0 has two real roots A and B where A < –1 and B > 1, then
- \(1+\left|\frac{\mathrm{b}}{\mathrm{a}}\right|+\frac{\mathrm{c}}{\mathrm{a}}<0\)
- \(1-\left|\frac{\mathrm{b}}{\mathrm{a}}\right|+\frac{\mathrm{c}}{\mathrm{a}}<0\)
- |c| < |a|
- |c| < |a| – |b|
Answer
(A) 1+ | b a |+ c a <0, (B) 1- | b a |+ c a <0
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