In the reaction : CO _ 2 ( ~g )+ H _ 2 ( ~g ) CO ( ~g )+ H _ 2 O ( ~g ) ∆H = 2.8 kJ then…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
In the reaction :
\(\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g}) \longrightarrow \mathrm{CO}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{~g})\)
∆H = 2.8 kJ
then ∆H represents
\(\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g}) \longrightarrow \mathrm{CO}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{~g})\)
∆H = 2.8 kJ
then ∆H represents
- heat of formation
- heat of reaction
- heat of solution
- heat of combustion
Answer
(B) heat of reaction
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