If S + O 2 → SO 2 ∆H = –298.2 kJ SO _ 2 + 1 2 O _ 2 SO _ 3 ∆H = –98.2 kJ SO _ 3 + H _ 2 O H _ 2 SO _ 4 ∆H = –130.2 kJ H _ 2 + 1 2 O _ 2 H _ 2 O ∆H = –287.3 kJ the enthalpy of formation of H 2 SO 4 at 298 K will be

If S + O 2 → SO 2 ∆H = –298.2 kJ SO _ 2 + 1 2 O _ 2 SO _ 3 ∆H = –98.2 kJ SO _ 3 + H _ 2 O…

Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics

If S + O₂ \(\text { → }\) SO₂ ∆H = –298.2 kJ
\(\mathrm{SO}_{2}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{SO}_{3}\) ∆H = –98.2 kJ
\(\mathrm{SO}_{3}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}_{2} \mathrm{SO}_{4}\) ∆H = –130.2 kJ
\(\mathrm{H}_{2}+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O}\) ∆H = –287.3 kJ
the enthalpy of formation of H₂SO₄ at 298 K will be

–433.7 kJ
–650.3 kJ
+320.5 kJ
–813.9 kJ

Answer

(D) –813.9 kJ

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If S + O 2 → SO 2 ∆H = –298.2 kJ SO _ 2 + 1 2 O _ 2 SO _ 3 ∆H = –98.2 kJ SO _ 3 + H _ 2 O…

Answer

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