Using the following energy values, determine the lattice energy of KF(s): array ll…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
Using the following energy values, determine the lattice energy of KF(s):
\[\begin{array}{ll} \text { Property } & \text { Energy }\left(\mathbf{k J} \mathbf{~ m o l}^{-1}\right) \\ \Delta \mathrm{H}_{\text {atomization }} \text { of } \mathrm{K}(\mathrm{~s}) & 90 \\ \Delta \mathrm{H}_{\text {atomization }} \text { of } \mathrm{F}_{2}(\mathrm{~g}) & 158 \\ \Delta \mathrm{H}_{\mathrm{f}} \text { of } \mathrm{KF}(\mathrm{~s}) & -567 \\ \mathrm{IE} \text { of } \mathrm{K}(\mathrm{~g}) & 419 \\ \mathrm{EA} \text { of } \mathrm{F}(\mathrm{~g}) & 328 \\ \text { (a) } 51 \mathrm{~kJ} & \text { (b) }+827 \mathrm{~kJ} \\ \text { (c) }+1145 \mathrm{~kJ} & \text { (d) }+1483 \mathrm{~kJ} \end{array}\]
\[\begin{array}{ll} \text { Property } & \text { Energy }\left(\mathbf{k J} \mathbf{~ m o l}^{-1}\right) \\ \Delta \mathrm{H}_{\text {atomization }} \text { of } \mathrm{K}(\mathrm{~s}) & 90 \\ \Delta \mathrm{H}_{\text {atomization }} \text { of } \mathrm{F}_{2}(\mathrm{~g}) & 158 \\ \Delta \mathrm{H}_{\mathrm{f}} \text { of } \mathrm{KF}(\mathrm{~s}) & -567 \\ \mathrm{IE} \text { of } \mathrm{K}(\mathrm{~g}) & 419 \\ \mathrm{EA} \text { of } \mathrm{F}(\mathrm{~g}) & 328 \\ \text { (a) } 51 \mathrm{~kJ} & \text { (b) }+827 \mathrm{~kJ} \\ \text { (c) }+1145 \mathrm{~kJ} & \text { (d) }+1483 \mathrm{~kJ} \end{array}\]
- 51 kJ
- + 827 kJ
- + 1145 kJ
- + 1483 kJ
Answer
(B) + 827 kJ
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