Calculate the heat of formation of PCl 5 (s) from the following data : 2P(s) + 3Cl 2 (g)…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
Calculate the heat of formation of PCl5(s) from the following data :
2P(s) + 3Cl2(g) \(\text { ⟶ }\) 2PCl3(l) ∆H = –151.8 kcal
PCl3(l) + Cl2(g) \(\text { ⟶ }\) PCl5(s) ∆H = –32.8 kcal
2P(s) + 3Cl2(g) \(\text { ⟶ }\) 2PCl3(l) ∆H = –151.8 kcal
PCl3(l) + Cl2(g) \(\text { ⟶ }\) PCl5(s) ∆H = –32.8 kcal
- –108.7 kcal
- 108.7 kcal
- –184.6 kcal
- 184.6 kcal
Answer
(A) –108.7 kcal
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