For the reaction at 300 K A(g) + B(g) → C(g) ∆U = –3.0 kcal ∆S = –10.0 cal/K (R ≈ 2 cal mol –1 K –1 ) ∆G is :

For the reaction at 300 K A(g) + B(g) → C(g) ∆U = –3.0 kcal ∆S = –10.0 cal/K (R ≈ 2 cal…

Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics

For the reaction at 300 K
A(g) + B(g) \(\text { → }\) C(g)
∆U = –3.0 kcal ∆S = –10.0 cal/K
(R ≈ 2 cal mol^–1 K^–1)
∆G is :

(A) –600 cal

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