In the given figure the variation of potential energy of a particle of mass m = 2 kg is…
Physics · JEE Advanced · NTA Exams — Work, Energy and Power
In the given figure the variation of potential energy of a particle of mass m = 2 kg is represented w.r.t. its x-coordinate. The particle moves under the effect of the conservative force along the x-axis. which of the following statements is incorrect about the particle?
- If it is released at the origin, it will move in negative x-axis
- If it is released at x = 2 + where 0, then its maximum speed will be 5 m/s and it will perform oscillatory motion
- If initially x = –10 and then it will cross x = 10
- x = –5 and x = +5 are unstable equilibrium positions of the particle
Answer
(D) x = –5 and x = +5 are unstable equilibrium positions of the particle
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