A force F =(3 x y-5 z) +4 z k is applied on a particle. The work done by the force when…
Physics · JEE Advanced · NTA Exams — Work, Energy and Power
A force \(\vec{F}=(3 x y-5 z) \hat{\jmath}+4 z \hat{k}\) is applied on a particle. The work done by the force when the particle moves from point (0, 0, 0) to point (2, 4, 0) as shown in the figure is


- \(\frac{280}{5}\)
- \(\frac{140}{5}\)
- \(\frac{232}{5}\)
- \(\frac{192}{5}\)
Answer
(D) 192 5
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Assertion: A weightlifter does not work in holding the weight up. Reason: Work done is zero because distance…
- A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging…
- A tennis ball is dropped on a horizontal smooth surface. It bounces back to its original position after…
- A body is lifted over route I and then route II such that force is always tangent to the path. Coefficient of…
- If the speed of a vehicle increases by 2 m/s, its K.E. is doubled. The original speed of the vehicle was
- A particle moves in a straight line with retardation proportional to its displacement. Its loss of KE for any…
- The potential energy for a force field is given by U (x, y) = cos (x + y). The force acting on a particle at…
- A machine, which is 75% efficient, uses 12 J of energy in lifting up a 1 kg mass through a certain distance…
More Work, Energy and Power questions · Browse all practice questions