The potential energy for a force field is given by U (x, y) = cos (x + y). The force…
Physics · JEE Advanced · NTA Exams — Work, Energy and Power
The potential energy for a force field is given by U (x, y) = cos (x + y). The force acting on a particle at position given by coordinates \(\left(0, \frac{\pi}{4}\right)\) is
- \(-\frac{1}{\sqrt{2}}(\hat{i}+\hat{j})\)
- \(\frac{1}{\sqrt{2}}(\hat{i}+\hat{j})\)
- \(\left(\frac{1}{2} \hat{i}+\frac{\sqrt{3}}{2} \hat{j}\right)\)
- \(\left(\frac{1}{2} \hat{i}-\frac{\sqrt{3}}{2} \hat{j}\right)\)
Answer
(B) 1 2 ( i + j )
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