Assertion: Two springs of force constants k1 and k2 are stretched by the same force. If…

Physics · JEE Advanced · NTA ExamsWork, Energy and Power

Assertion: Two springs of force constants k1 and k2 are stretched by the same force. If k1 > k2, then work done in stretching the first spring (W1) is less than work done in stretching the second spring (W2).
 Reason: F = k1x1 = k2x2
 \(\text { ∴ }\) \(\frac{x_{1}}{x_{2}}=\frac{k_{2}}{k_{1}}\)
 \[\frac{W_{1}}{W_{2}}=\frac{\frac{1}{2} k_{1} x_{1}^{2}}{\frac{1}{2} k_{2} x_{2}^{2}}=\frac{k_{1}}{k_{2}}\left(\frac{k_{2}}{k_{1}}\right)^{2}=\frac{k_{2}}{k_{1}}\]
 As k1 > k2, W1 < W2
  1. If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
  2. If both Assertion and Reason are true but Reason is not correct explanation of the Assertion.
  3. If Assertion is true but Reason is false.
  4. If Assertion is false but Reason is true.

Answer

(A) If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.

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