A particle A is projected vertically upwards. Another particle B of same mass is…
Physics · JEE Advanced · NTA Exams — Kinematics
A particle A is projected vertically upwards. Another particle B of same mass is projected at an angle of 45o. Both reach the same height. The ratio of the initial kinetic energy of A to that of B is [given \(\mathrm{KE}=\frac{1}{2} \mathrm{mv} \mathrm{v}^{2}\)]
- 1:2
- 2:1
- \(1: \sqrt{2}\)
- \(\sqrt{2}: 1\)
Answer
(A) 1:2
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