A body of mass m is thrown upwards at an angle with the horizontal with velocity v. While…
Physics · JEE Advanced · NTA Exams — Kinematics
A body of mass m is thrown upwards at an angle \(\theta\) with the horizontal with velocity v. While rising up the velocity of the mass after t seconds will be
- \(\sqrt{(v \cos \theta)^{2}+(v \sin \theta)^{2}}\)
- \(\sqrt{(v \cos \theta-v \sin \theta)^{2}-g t}\)
- \(\sqrt{v^{2}+g^{2} t^{2}-(2 v \sin \theta) g t}\)
- \(\sqrt{v^{2}+g^{2} t^{2}-(2 v \cos \theta) g t}\)
Answer
(C) v^ 2 +g^ 2 t^ 2 -(2 v ) g t
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