If velocity of the particle is given by v= x , where x denotes the position of the…
Physics · JEE Advanced · NTA Exams — Kinematics
If velocity of the particle is given by \(v=\sqrt{x}\), where x denotes the position of the particle and initially particle was at x = 4, then which of the following are correct.
- at t = 2 sec, the position of the particle is at x = 9
- Particle acceleration at t = 2 sec. is 1 m/s2.
- Particle acceleration is 1/2 m/s2 throughout the motion.
- Particle will never go in negative direction from its starting position.
Answer
(A) at t = 2 sec, the position of the particle is at x = 9, (C) Particle acceleration is 1/2 m/s2 throughout the motion., (D) Particle will never go in negative direction from its starting position.
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