As a rocket is accelerating vertically upwards at 9.8 m/s2 near the earth’s surface, it…
Physics · JEE Advanced · NTA Exams — Kinematics
As a rocket is accelerating vertically upwards at 9.8 m/s2 near the earth’s surface, it releases a projectile. Immediately after release, the acceleration (in m/s2) of the projectile, is (Take g = 9.8 m/s2)
- zero
- 9.8 m/s2 up
- 9.8 m/s2 down
- 19.6 m/s2 up
Answer
(C) 9.8 m/s2 down
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