A particle is projected from the ground with an initial speed of u at an angle with…
Physics · JEE Advanced · NTA Exams — Kinematics
A particle is projected from the ground with an initial speed of u at an angle \(\theta\) with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is
- \(\frac{u}{2} \sqrt{1+2 \cos ^{2} \theta}\)
- \(\frac{u}{2} \sqrt{1+\cos ^{2} \theta}\)
- \(\frac{u}{2} \sqrt{1+3 \cos ^{2} \theta}\)
- \(\text { u } \cos \theta\)
Answer
(C) u 2 1+3 ^ 2
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