A particle is projected up an inclined plane with initial speed v = 20 m/s at an angle…
Physics · JEE Advanced · NTA Exams — Kinematics
A particle is projected up an inclined plane with initial speed v = 20 m/s at an angle \(\theta=30^{\circ}\) with plane. The component of its velocity perpendicular to plane when it strikes the plane is
- \(10 \sqrt{3} \mathrm{~m} / \mathrm{s}\)
- 10 m/s
- \(5 \sqrt{3} \mathrm{~m} / \mathrm{s}\)
- data is insufficient
Answer
(B) 10 m/s
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