The emf of a Daniell cell at 298 K is E 1. Zn | array c ZnSO _ 4 10.01 M , array | |…
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
The emf of a Daniell cell at 298 K is E1.
\(\mathrm{Zn}\left|\begin{array}{c} \mathrm{ZnSO}_{4} \\ 10.01 \mathrm{M}, \end{array}\right|\left|\begin{array}{ccc} \mathrm{CuSO}_{4} & \mathrm{Cu} \\ 1.0 \mathrm{M}, 0 \end{array}\right|\)
When the concentration of ZnSO4 is 1.0M and that of CuSO4 is 0.01M, the emf changed to E2. What is the relationship between E1 and E2?
- E1 = E2
- E2 = 0 ≠ E1
- E1 > E2
- E1 < E2
Answer
(C) E 1 > E 2
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