Electrode potential data are given below: array ll Fe ^ 2+ +2 e ^ - Fe (5): & E ^ a…
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
Electrode potential data are given below:
\[\begin{array}{ll} \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Fe}(5): & \mathrm{E}^{a}=-0.44 \mathrm{~V} \\ \mathrm{Al}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Al}(5): & \mathrm{E}^{a}=-1.66 \mathrm{~V} \\ \mathrm{Br}_{2}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Zr}^{-}(\mathrm{aq}): & \mathrm{E}^{a}=1.08 \mathrm{~V} \end{array}\]
Based on the given data, arrange Fe2+ , Al, Br- in increasing order of reducing power.
- Br- < Fe2+ < Al
- Fe2+ < Al < Br-
- Al < Br- < Fe2+
- Al < Fe2+ < Br-
Answer
(D) Al < Fe 2 + < Br -
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