Electrode potential data are given below: array ll Fe ^ 2+ +2 e ^ - Fe (5): & E ^ a…

Chemistry · JEE Main · NTA ExamsRedox Reactions and Electrochemistry

Electrode potential data are given below:

\[\begin{array}{ll} \mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Fe}(5): & \mathrm{E}^{a}=-0.44 \mathrm{~V} \\ \mathrm{Al}^{3+}+3 \mathrm{e}^{-} \longrightarrow \mathrm{Al}(5): & \mathrm{E}^{a}=-1.66 \mathrm{~V} \\ \mathrm{Br}_{2}+2 \mathrm{e}^{-} \longrightarrow \mathrm{Zr}^{-}(\mathrm{aq}): & \mathrm{E}^{a}=1.08 \mathrm{~V} \end{array}\]

Based on the given data, arrange Fe2+ ,  Al, Br- in increasing order of reducing power.

  1. Br- < Fe2+ < Al
  2. Fe2+ < Al < Br-
  3. Al < Br- < Fe2+
  4. Al < Fe2+ < Br-

Answer

(D) Al < Fe 2 + < Br -

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