When two half-cells of electrode potential of E 1 and E 2 are combined to form a cell of…

Chemistry · JEE Main · NTA ExamsRedox Reactions and Electrochemistry

When two half-cells of electrode potential of E1 and E2 are combined to form a cell of electrode potential E3, then (when n1, n2 and n3 are no. of electrons exchanged in first, second and combined half-cells) :
  1. E3 = E2 – E1
  2. E3 = \(\frac{\mathrm{E}_{1} \mathrm{n}_{1}+\mathrm{E}_{2} \mathrm{n}_{2}}{\mathrm{n}_{3}}\)
  3. E3 = \(\frac{\mathrm{E}_{1} \mathrm{n}_{1}-\mathrm{E}_{2} \mathrm{n}_{2}}{\mathrm{n}_{3}^{2}}\)
  4. E3 = E1 + E2

Answer

(B) E 3 = E _ 1 n _ 1 + E _ 2 n _ 2 n _ 3

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