The rate of flow of heat depends on the nature of material, cross-sectional area and…
Physics · JEE Advanced · NTA Exams — Thermodynamics
The rate of flow of heat depends on the nature of material, cross-sectional area and temperature gradient. If a material of conductivity k has set up a temperature gradient in x direction, then rate of heat flow at cross-section having area A is \(\frac{\mathrm{dQ}}{\mathrm{dt}}=\mathrm{k} \mathrm{~A} \frac{\mathrm{dT}}{\mathrm{dx}}\)
Between any two points of conductor, if temperature difference is \(\Delta \mathrm{T}\) and rate of heat flow is H, then the resistance or opposition offered by the material to flow is defined as =\(\frac{\Delta \mathrm{T}}{\mathrm{H}}\). Now consider two very thin concentric metallic shells A and B of radii R1 and R2 (R2 > R1) and temperature T1 and T2 (T1 > T2) respectively. The hollow space between them is filled with sand of thermal conductivity k.
Thermal resistance offered by the sand is
- \(\frac{1}{2 \pi \mathrm{k}}\left(\frac{1}{\mathrm{R}_{1}}-\frac{1}{\mathrm{R}_{2}}\right)\)
- \(\frac{1}{4 \pi \mathrm{k}}\left(\frac{1}{\mathrm{R}_{1}}-\frac{1}{\mathrm{R}_{2}}\right)\)
- \(4 \pi \mathrm{k}\left(\frac{1}{\mathrm{R}_{1}}-\frac{1}{\mathrm{R}_{2}}\right)\)
- \(2 \pi \mathrm{k}\left(\frac{1}{\mathrm{R}_{1}}-\frac{1}{\mathrm{R}_{2}}\right)\)
Answer
(B) 1 4 k ( 1 R _ 1 - 1 R _ 2 )
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