A black body radiates power P and maximum energy is radiated by it around a wavelength λ…
Physics · JEE Advanced · NTA Exams — Thermodynamics
A black body radiates power P and maximum energy is radiated by it around a wavelength λ0 . The temperature of the black body is now changed such that it radiates maximum energy around the wavelength \(\frac{3 \lambda_{0}}{4} .\) The power radiated by it now is :
- \(\frac{256}{8} \mathrm{P}\)
- \(\frac{\mathbb{Z}}{6} \mathrm{P}\)
- \(\frac{6}{2} \mathrm{P}\)
- \(\frac{8}{256} \mathrm{P}\)
Answer
(A) 256 8 P
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