A particle moves in the X-Y plane under the influence of a force such that its linear…
Physics · JEE Advanced · NTA Exams — Kinematics
A particle moves in the X-Y plane under the influence of a force such that its linear momentum is \(\vec{p}(t)=A[\hat{i} \cos (k t)-\hat{j} \sin (k t)],\) where A and k are constants. The angle between the force and the momentum is
- 0°
- 30°
- 45°
- 90°
Answer
(D) 90°
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