A ball is projected horizontally with a speed v from the top of a plane inclined at an…
Physics · JEE Advanced · NTA Exams — Kinematics
A ball is projected horizontally with a speed v from the top of a plane inclined at an angle 45° with the horizontal. How far from the point of projection will the ball strike the plane?
- \(\frac{v^{2}}{g}\)
- \(\sqrt{2} \frac{\mathrm{v}^{2}}{\mathrm{~g}}\)
- \(\frac{2 v^{2}}{g}\)
- \(\sqrt{2}\left[\frac{2 v^{2}}{g}\right]\)
Answer
(D) 2 [ 2 v^ 2 g ]
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