A stone is thrown vertically upward with an initial velocity v0. The distance travelled…
Physics · JEE Advanced · NTA Exams — Kinematics
A stone is thrown vertically upward with an initial velocity v0. The distance travelled in time 4v0/3g is
- \(\frac{2 v_{0}^{2}}{g}\)
- \(\frac{v_{0}^{2}}{2 g}\)
- \(\frac{4 v_{0}^{2}}{3 g}\)
- \(\frac{5 v_{0}^{2}}{9 g}\)
Answer
(D) 5 v_ 0 ^ 2 9 g
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