The height y and the distance x along the horizontal plane of a projectile on a certain…
Physics · JEE Advanced · NTA Exams — Kinematics
The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t – 5) metre and x = 6t metre where t is in seconds. The velocity of projection is
- 8 m/sec
- 6 m/sec
- 10 m/sec
- not obtained from the data
Answer
(C) 10 m/sec
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A person measures the depth of a well by measuring the time interval between dropping a stone and receiving…
- A particle P is projected from a point on the surface of smooth inclined plane (see figure). Simultaneously…
- ext Let a = i + j + k , b = i - j + k ext and c = i - j - k be three vectors. A vector in the plane of a ext…
- A particle travels 10m in first 5 sec and 10m in next 3 sec. Assuming constant acceleration what is the…
- A particle of mass m moves on the x -axis as follows: It starts from rest at t = 0 from the point x = 0, and…
- The displacement (x) of a particle depends on time (t) as x= t^ 2 - t^ 3
- The velocity v and displacement r of a body are related as v2 = kr, where k is a constant. What will be the…
- Let two non-collinear unit vectors and form an acute angle. A point P moves so that at any time t the…