Velocity and acceleration of a particle initially are v =(3 i +4 j ) m/s and a =-(6 i +8…
Physics · JEE Advanced · NTA Exams — Kinematics
Velocity and acceleration of a particle initially are \(\overrightarrow{\mathrm{v}}=(3 \hat{\mathrm{i}}+4 \hat{\mathrm{j}})\)m/s and \(\bar{a}=-(6 \hat{i}+8 \hat{j})\)m/s2 respectively. Initially particle is at origin. maximum x–coordinate of particle will be:
- 1.5 m
- 0.75 m
- 2.25 m
- 4.0 m
Answer
(B) 0.75 m
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