A satellite of mass m is orbiting the earth (of radius R) at a height h from its surface…
Physics · JEE Main · NTA Exams — Gravitation
A satellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the satellite in terms of g0, the value of acceleration due to gravity at the earth's surface, is:
- \(\frac{2 m g_{n} R^{2}}{R+h}\)
- \(-\frac{2 m g_{n} R^{2}}{R+h}\)
- \(\frac{m g_{n} R^{2}}{2(R+h)}\)
- \(-\frac{m g_{n} R^{2}}{2(R+h)}\)
Answer
(D) - m g_ n R^ 2 2(R+h)
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