A body is released from a point distance r from the centre of the Earth. If R is the…
Physics · JEE Main · NTA Exams — Gravitation
A body is released from a point distance r from the centre of the Earth. If R is the radius of the Earth and r > R, then the velocity of the body at the time of striking the Earth will be
- \(\sqrt{g^{R}}\)
- \(\sqrt{2 g R}\)
- \(\sqrt{\frac{2 g R r}{r-R}}\)
- \(\sqrt{\operatorname{ZgR}\left(\frac{r-R}{r}\right)}\)
Answer
(D) ZgR ( r-R r )
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