For a satellite moving in an orbit around the Earth, the ratio of kinetic energy to…
Physics · JEE Main · NTA Exams — Gravitation
For a satellite moving in an orbit around the Earth, the ratio of kinetic energy to potential energy is:
- \(2\)
- \(\frac{1}{2}\)
- \(\frac{1}{\sqrt{2}}\)
- \(\sqrt{2}\)
Answer
(B) 1 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Given below are two statements: One is labelled as Assertion (A) and the other is labelled as Reason (R)…
- If a man at the equator would weigh ( 3 5 ) th of his actual weight, the angular speed of the earth is
- The kinetic energy of a satellite in its orbit around the Earth is E. Its kinetic energy, so as to enable it…
- A high jumper can jump 2.0 m on earth. With the same effort how high will he be able to jump on a planet…
- Assuming earth to be a sphere of uniform density. What is the value of acceleration due to gravity at a point…
- Two satellites A and B of masses m 1 and m 2 (m 1 = 2m 2 ) are moving in circular orbits of radii r 1 and r 2…
- Assertion: The comet does not obey Kepler’s law of planetary motion. Reason: The comet does not have…
- The height of the point vertically above the earth’s surface at which the acceleration due to gravity becomes…