The equation of ellipse whose axes are coincident with the coordinate axes and which…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The equation of ellipse whose axes are coincident with the coordinate axes and which touches the straight lines \(3 x-2 y-20=0\) and \(x+6 y-20=0\), is
- \(\frac{x^{2}}{5}+\frac{y^{2}}{8}=1\)
- \(\frac{x^{2}}{40}+\frac{y^{2}}{10}=10\)
- \(\frac{x^{2}}{40}+\frac{y^{2}}{10}=1\)
- \(\frac{x^{2}}{10}+\frac{y^{2}}{40}=1\)
Answer
(C) x^ 2 40 + y^ 2 10 =1
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