_ -1 ^ 3 ( ^ -1 x x^ 2 +1 + ^ -1 x^ 2 +1 x ) d x equals to
Mathematics · JEE Main · NTA Exams — Integral Calculus
\(\int_{-1}^{3}\left(\tan ^{-1} \frac{x}{x^{2}+1}+\tan ^{-1} \frac{x^{2}+1}{x}\right) d x\) equals to
- \(2 \pi\)
- \(\pi\)
- \(4 \pi\)
- none
Answer
(B)
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