The value of the integral _ e^ -1 ^ e^ 2 | _ e x x | d x is,
Mathematics · JEE Main · NTA Exams — Integral Calculus
The value of the integral \[\int_{e^{-1}}^{e^{2}}\left|\frac{\log _{e} x}{x}\right| d x\] is,
- 3/2
- 5/2
- 3
- 5
Answer
(B) 5/2
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