Liquid 'M' and liquid 'N' form an ideal solution. The vapour pressure of pure liquids 'M'…
Chemistry · JEE Main · NTA Exams — Solutions
Liquid 'M' and liquid 'N' form an ideal solution. The vapour pressure of pure liquids 'M' and 'N' are 450 and 700 mmgHg, respectively, at the same temperature. Then correct statement is:
(xM = Mole fraction of 'M' in solution;
xN = Mole fraction of 'N' in solution;
yM = Mole fraction of 'M' in vapour phase;
yN = Mole fraction of 'N' in vapour phase)
- \(\frac{x_{M}}{x_{N}}<\frac{y_{M}}{y_{N}}\)
- \(\frac{x_{M}}{x_{N}}=\frac{y_{M}}{y_{N}}\)
- \(\frac{x_{M}}{x_{N}}>\frac{y_{M}}{y_{N}}\)
- \(\left(x_{M}-y_{M}\right)<\left(x_{N}-y_{N}\right)\)
Answer
(A) x_ M x_ N < y_ M y_ N
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