The molar freezing point constant for water is 1.86º C/m. If 342g of cane sugar (C 12 H…
Chemistry · JEE Main · NTA Exams — Solutions
The molar freezing point constant for water is 1.86º C/m. If 342g of cane sugar (C12H22O11) is dissolved in 1000 g of water, the solution will freeze at
- –1.86º
- 1.86ºC
- –3.92ºC
- 2.42ºC
Answer
(A) –1.86º
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