Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on…
Chemistry · JEE Main · NTA Exams — Solutions
Vapour pressure of a pure liquid X is 2 atm at 300 K. It is lowered to 1 atm on dissolving 1g of Y in 20g of liquid X. If molar mass of X is 200, what is the molar mass of Y ?
- 20
- 10
- 100
- 30
Answer
(A) 20
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