What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure…
Chemistry · JEE Main · NTA Exams — Solutions
What weight of glucose must be dissolved in 100 g of water to lower the vapour pressure by 0.20 mm Hg?
(Assume dilute solution is being formed)
Given: Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-\mathrm{h}}\) (Jee Main 2023)
(Assume dilute solution is being formed)
Given: Vapour pressure of pure water is 54.2 mm Hg at room temperature. Molar mass of glucose is \(180 \mathrm{~g} \mathrm{~mol}^{-\mathrm{h}}\) (Jee Main 2023)
- 4.69 g
- 3.59 g
- 3.69 g
- 2.59 g
Answer
(C) 3.69 g
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